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An architect designs a rectangular flower garden such that the width is exactly two-thirds of the length.If 3000 feet of antique picket fencing are to be used to enclose the garden ,find the dimensions of the garden . Find the length of the garden ,and the width of the garden ....thanks your help

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1. Let x = the length of the garden then, (2/3)x = the width of the garden The perimeter is: P = 2x + 2(2/3)x = (10/3)x = 3000 solve for x...you can do it. You must do it. [x = 900 ft. the dimensions of the rectangular plot are 900 ft by 600 ft]
2. Length—w: 2(x + 2/3x) = 3,000 x + 2/3x = 1,500 3x + 2x = 4,500 5x = 4,500 x = 900 Width: = 2/3(900) = 1,800/3 or 600 Answer: 900 feet by 600 feet are the dimensions.
3. let x be the length of the garden therefore (2/3)*x = the width the perimeter of the garden is twice the width + twice the length = (4/3)*x + 2x = (10/3)*x (10/3)*x = 3000 feet x = 3000/(10/3) x = 9000/10 = 900 length = 900 feet width = (2/3)*900 = 600 feet